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3(2x-2)=2(3)
We move all terms to the left:
3(2x-2)-(2(3))=0
determiningTheFunctionDomain 3(2x-2)-23=0
We multiply parentheses
6x-6-23=0
We add all the numbers together, and all the variables
6x-29=0
We move all terms containing x to the left, all other terms to the right
6x=29
x=29/6
x=4+5/6
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