3(2x-2)=2(x-3)+4x

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Solution for 3(2x-2)=2(x-3)+4x equation: 



3(2x-2)=2(x-3)+4x

We move all terms to the left:

3(2x-2)-(2(x-3)+4x)=0

We multiply parentheses

6x-(2(x-3)+4x)-6=0



We calculate terms in parentheses: -(2(x-3)+4x), so:

2(x-3)+4x

We add all the numbers together, and all the variables

4x+2(x-3)

We multiply parentheses

4x+2x-6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

6x-6x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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