3(2x-2)=4(x+3)+4x

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Solution for 3(2x-2)=4(x+3)+4x equation: 



3(2x-2)=4(x+3)+4x

We move all terms to the left:

3(2x-2)-(4(x+3)+4x)=0

We multiply parentheses

6x-(4(x+3)+4x)-6=0



We calculate terms in parentheses: -(4(x+3)+4x), so:

4(x+3)+4x

We add all the numbers together, and all the variables

4x+4(x+3)

We multiply parentheses

4x+4x+12

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

6x-8x-12-6=0

We add all the numbers together, and all the variables

-2x-18=0

We move all terms containing x to the left, all other terms to the right

-2x=18

x=18/-2

x=-9

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