3(2x-2+6x)=2(3x-4)

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Solution for 3(2x-2+6x)=2(3x-4) equation: 



3(2x-2+6x)=2(3x-4)

We move all terms to the left:

3(2x-2+6x)-(2(3x-4))=0

We add all the numbers together, and all the variables

3(8x-2)-(2(3x-4))=0

We multiply parentheses

24x-(2(3x-4))-6=0



We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

24x-6x+8-6=0

We add all the numbers together, and all the variables

18x+2=0

We move all terms containing x to the left, all other terms to the right

18x=-2

x=-2/18

x=-1/9

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