3(2x-3)+1=(3x-1)-2(x-4)

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Solution for 3(2x-3)+1=(3x-1)-2(x-4) equation: 



3(2x-3)+1=(3x-1)-2(x-4)

We move all terms to the left:

3(2x-3)+1-((3x-1)-2(x-4))=0

We multiply parentheses

6x-((3x-1)-2(x-4))-9+1=0



We calculate terms in parentheses: -((3x-1)-2(x-4)), so:

(3x-1)-2(x-4)

We multiply parentheses

(3x-1)-2x+8

We get rid of parentheses

3x-2x-1+8

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We add all the numbers together, and all the variables

6x-(x+7)-8=0

We get rid of parentheses

6x-x-7-8=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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