3(2x-3)+2(7x+2)=23

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Solution for 3(2x-3)+2(7x+2)=23 equation: 



3(2x-3)+2(7x+2)=23

We move all terms to the left:

3(2x-3)+2(7x+2)-(23)=0

We multiply parentheses

6x+14x-9+4-23=0

We add all the numbers together, and all the variables

20x-28=0

We move all terms containing x to the left, all other terms to the right

20x=28

x=28/20

x=1+2/5

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