3(2x-3)+2(x+4)=-5(x-5)+13

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Solution for 3(2x-3)+2(x+4)=-5(x-5)+13 equation: 



3(2x-3)+2(x+4)=-5(x-5)+13

We move all terms to the left:

3(2x-3)+2(x+4)-(-5(x-5)+13)=0

We multiply parentheses

6x+2x-(-5(x-5)+13)-9+8=0



We calculate terms in parentheses: -(-5(x-5)+13), so:

-5(x-5)+13

We multiply parentheses

-5x+25+13

We add all the numbers together, and all the variables

-5x+38

Back to the equation:

-(-5x+38)



We add all the numbers together, and all the variables

8x-(-5x+38)-1=0

We get rid of parentheses

8x+5x-38-1=0

We add all the numbers together, and all the variables

13x-39=0

We move all terms containing x to the left, all other terms to the right

13x=39

x=39/13

x=3

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