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3(2x-3)+2(x+4)=-5(x-5)+13
We move all terms to the left:
3(2x-3)+2(x+4)-(-5(x-5)+13)=0
We multiply parentheses
6x+2x-(-5(x-5)+13)-9+8=0
We calculate terms in parentheses: -(-5(x-5)+13), so:We add all the numbers together, and all the variables
-5(x-5)+13
We multiply parentheses
-5x+25+13
We add all the numbers together, and all the variables
-5x+38
Back to the equation:
-(-5x+38)
8x-(-5x+38)-1=0
We get rid of parentheses
8x+5x-38-1=0
We add all the numbers together, and all the variables
13x-39=0
We move all terms containing x to the left, all other terms to the right
13x=39
x=39/13
x=3
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