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3(2x-3)+4(x+2)=2(5x-2)
We move all terms to the left:
3(2x-3)+4(x+2)-(2(5x-2))=0
We multiply parentheses
6x+4x-(2(5x-2))-9+8=0
We calculate terms in parentheses: -(2(5x-2)), so:We add all the numbers together, and all the variables
2(5x-2)
We multiply parentheses
10x-4
Back to the equation:
-(10x-4)
10x-(10x-4)-1=0
We get rid of parentheses
10x-10x+4-1=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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