3(2x-3)+5=2(3x-2)

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Solution for 3(2x-3)+5=2(3x-2) equation:



3(2x-3)+5=2(3x-2)
We move all terms to the left:
3(2x-3)+5-(2(3x-2))=0
We multiply parentheses
6x-(2(3x-2))-9+5=0
We calculate terms in parentheses: -(2(3x-2)), so:
2(3x-2)
We multiply parentheses
6x-4
Back to the equation:
-(6x-4)
We add all the numbers together, and all the variables
6x-(6x-4)-4=0
We get rid of parentheses
6x-6x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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