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3(2x-3)+8(x-4)=2(2x+6)
We move all terms to the left:
3(2x-3)+8(x-4)-(2(2x+6))=0
We multiply parentheses
6x+8x-(2(2x+6))-9-32=0
We calculate terms in parentheses: -(2(2x+6)), so:We add all the numbers together, and all the variables
2(2x+6)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
14x-(4x+12)-41=0
We get rid of parentheses
14x-4x-12-41=0
We add all the numbers together, and all the variables
10x-53=0
We move all terms containing x to the left, all other terms to the right
10x=53
x=53/10
x=5+3/10
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