3(2x-3)+8=3-2(1-3x)

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Solution for 3(2x-3)+8=3-2(1-3x) equation: 



3(2x-3)+8=3-2(1-3x)

We move all terms to the left:

3(2x-3)+8-(3-2(1-3x))=0

We add all the numbers together, and all the variables

3(2x-3)-(3-2(-3x+1))+8=0

We multiply parentheses

6x-(3-2(-3x+1))-9+8=0



We calculate terms in parentheses: -(3-2(-3x+1)), so:

3-2(-3x+1)

determiningTheFunctionDomain
-2(-3x+1)+3

We multiply parentheses

6x-2+3

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We add all the numbers together, and all the variables

6x-(6x+1)-1=0

We get rid of parentheses

6x-6x-1-1=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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