3(2x-3)+x(+x+36)=103

Solution for 3(2x-3)+x(+x+36)=103 equation:

3(2x-3)+x(+x+36)=103

We move all terms to the left:

3(2x-3)+x(+x+36)-(103)=0

We add all the numbers together, and all the variables

3(2x-3)+x(x+36)-103=0

We multiply parentheses

x^2+6x+36x-9-103=0

We add all the numbers together, and all the variables

x^2+42x-112=0

a = 1; b = 42; c = -112;
Δ = b2-4ac
Δ = 422-4·1·(-112)
Δ = 2212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2212}=\sqrt{4*553}=\sqrt{4}*\sqrt{553}=2\sqrt{553}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-2\sqrt{553}}{2*1}=\frac{-42-2\sqrt{553}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+2\sqrt{553}}{2*1}=\frac{-42+2\sqrt{553}}{2}
$