3(2x-3)+x=4(x+2)

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Solution for 3(2x-3)+x=4(x+2) equation: 



3(2x-3)+x=4(x+2)

We move all terms to the left:

3(2x-3)+x-(4(x+2))=0

We add all the numbers together, and all the variables

x+3(2x-3)-(4(x+2))=0

We multiply parentheses

x+6x-(4(x+2))-9=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

7x-(4x+8)-9=0

We get rid of parentheses

7x-4x-8-9=0

We add all the numbers together, and all the variables

3x-17=0

We move all terms containing x to the left, all other terms to the right

3x=17

x=17/3

x=5+2/3

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