3(2x-3)-5=16+4x

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Solution for 3(2x-3)-5=16+4x equation: 



3(2x-3)-5=16+4x

We move all terms to the left:

3(2x-3)-5-(16+4x)=0

We add all the numbers together, and all the variables

3(2x-3)-(4x+16)-5=0

We multiply parentheses

6x-(4x+16)-9-5=0

We get rid of parentheses

6x-4x-16-9-5=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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