3(2x-3)=2(2x-4)-1/3

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Solution for 3(2x-3)=2(2x-4)-1/3 equation: 



3(2x-3)=2(2x-4)-1/3

We move all terms to the left:

3(2x-3)-(2(2x-4)-1/3)=0

We multiply parentheses

6x-(2(2x-4)-1/3)-9=0

We multiply all the terms by the denominator


6x*3)-(2(2x-4)-1-9*3)=0

We add all the numbers together, and all the variables

6x*3)-(2(2x-4)=0

Wy multiply elements

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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