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3(2x-3)=2(4-3x)+5
We move all terms to the left:
3(2x-3)-(2(4-3x)+5)=0
We add all the numbers together, and all the variables
3(2x-3)-(2(-3x+4)+5)=0
We multiply parentheses
6x-(2(-3x+4)+5)-9=0
We calculate terms in parentheses: -(2(-3x+4)+5), so:We get rid of parentheses
2(-3x+4)+5
We multiply parentheses
-6x+8+5
We add all the numbers together, and all the variables
-6x+13
Back to the equation:
-(-6x+13)
6x+6x-13-9=0
We add all the numbers together, and all the variables
12x-22=0
We move all terms containing x to the left, all other terms to the right
12x=22
x=22/12
x=1+5/6
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