3(2x-3)=3(2x-4)+3

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Solution for 3(2x-3)=3(2x-4)+3 equation: 



3(2x-3)=3(2x-4)+3

We move all terms to the left:

3(2x-3)-(3(2x-4)+3)=0

We multiply parentheses

6x-(3(2x-4)+3)-9=0



We calculate terms in parentheses: -(3(2x-4)+3), so:

3(2x-4)+3

We multiply parentheses

6x-12+3

We add all the numbers together, and all the variables

6x-9

Back to the equation:

-(6x-9)



We get rid of parentheses

6x-6x+9-9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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