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3(2x-3)=3(2x-4)+3
We move all terms to the left:
3(2x-3)-(3(2x-4)+3)=0
We multiply parentheses
6x-(3(2x-4)+3)-9=0
We calculate terms in parentheses: -(3(2x-4)+3), so:We get rid of parentheses
3(2x-4)+3
We multiply parentheses
6x-12+3
We add all the numbers together, and all the variables
6x-9
Back to the equation:
-(6x-9)
6x-6x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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