3(2x-3)=3x-2(2x-1)

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Solution for 3(2x-3)=3x-2(2x-1) equation: 



3(2x-3)=3x-2(2x-1)

We move all terms to the left:

3(2x-3)-(3x-2(2x-1))=0

We multiply parentheses

6x-(3x-2(2x-1))-9=0



We calculate terms in parentheses: -(3x-2(2x-1)), so:

3x-2(2x-1)

We multiply parentheses

3x-4x+2

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We get rid of parentheses

6x+1x-2-9=0

We add all the numbers together, and all the variables

7x-11=0

We move all terms containing x to the left, all other terms to the right

7x=11

x=11/7

x=1+4/7

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