3(2x-3)=4(x+1)-3

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Solution for 3(2x-3)=4(x+1)-3 equation: 



3(2x-3)=4(x+1)-3

We move all terms to the left:

3(2x-3)-(4(x+1)-3)=0

We multiply parentheses

6x-(4(x+1)-3)-9=0



We calculate terms in parentheses: -(4(x+1)-3), so:

4(x+1)-3

We multiply parentheses

4x+4-3

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We get rid of parentheses

6x-4x-1-9=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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