3(2x-3)=6(x+1)-8

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Solution for 3(2x-3)=6(x+1)-8 equation: 



3(2x-3)=6(x+1)-8

We move all terms to the left:

3(2x-3)-(6(x+1)-8)=0

We multiply parentheses

6x-(6(x+1)-8)-9=0



We calculate terms in parentheses: -(6(x+1)-8), so:

6(x+1)-8

We multiply parentheses

6x+6-8

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

6x-6x+2-9=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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