3(2x-37)=11x+33-x

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Solution for 3(2x-37)=11x+33-x equation: 



3(2x-37)=11x+33-x

We move all terms to the left:

3(2x-37)-(11x+33-x)=0

We add all the numbers together, and all the variables

3(2x-37)-(10x+33)=0

We multiply parentheses

6x-(10x+33)-111=0

We get rid of parentheses

6x-10x-33-111=0

We add all the numbers together, and all the variables

-4x-144=0

We move all terms containing x to the left, all other terms to the right

-4x=144

x=144/-4

x=-36

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