3(2x-4)+10=20

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Solution for 3(2x-4)+10=20 equation: 



3(2x-4)+10=20

We move all terms to the left:

3(2x-4)+10-(20)=0

We add all the numbers together, and all the variables

3(2x-4)-10=0

We multiply parentheses

6x-12-10=0

We add all the numbers together, and all the variables

6x-22=0

We move all terms containing x to the left, all other terms to the right

6x=22

x=22/6

x=3+2/3

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