3(2x-4)+10=7(x-9)

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Solution for 3(2x-4)+10=7(x-9) equation: 



3(2x-4)+10=7(x-9)

We move all terms to the left:

3(2x-4)+10-(7(x-9))=0

We multiply parentheses

6x-(7(x-9))-12+10=0



We calculate terms in parentheses: -(7(x-9)), so:

7(x-9)

We multiply parentheses

7x-63

Back to the equation:

-(7x-63)



We add all the numbers together, and all the variables

6x-(7x-63)-2=0

We get rid of parentheses

6x-7x+63-2=0

We add all the numbers together, and all the variables

-1x+61=0

We move all terms containing x to the left, all other terms to the right

-x=-61

x=-61/-1

x=+61

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