3(2x-4)+16=6(2x-3)-5(3x-2)

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Solution for 3(2x-4)+16=6(2x-3)-5(3x-2) equation: 



3(2x-4)+16=6(2x-3)-5(3x-2)

We move all terms to the left:

3(2x-4)+16-(6(2x-3)-5(3x-2))=0

We multiply parentheses

6x-(6(2x-3)-5(3x-2))-12+16=0



We calculate terms in parentheses: -(6(2x-3)-5(3x-2)), so:

6(2x-3)-5(3x-2)

We multiply parentheses

12x-15x-18+10

We add all the numbers together, and all the variables

-3x-8

Back to the equation:

-(-3x-8)



We add all the numbers together, and all the variables

6x-(-3x-8)+4=0

We get rid of parentheses

6x+3x+8+4=0

We add all the numbers together, and all the variables

9x+12=0

We move all terms containing x to the left, all other terms to the right

9x=-12

x=-12/9

x=-1+1/3

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