3(2x-4)+2(3x-2)=2(6x-8)

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Solution for 3(2x-4)+2(3x-2)=2(6x-8) equation: 



3(2x-4)+2(3x-2)=2(6x-8)

We move all terms to the left:

3(2x-4)+2(3x-2)-(2(6x-8))=0

We multiply parentheses

6x+6x-(2(6x-8))-12-4=0



We calculate terms in parentheses: -(2(6x-8)), so:

2(6x-8)

We multiply parentheses

12x-16

Back to the equation:

-(12x-16)



We add all the numbers together, and all the variables

12x-(12x-16)-16=0

We get rid of parentheses

12x-12x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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