3(2x-4)+21x=15

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Solution for 3(2x-4)+21x=15 equation: 



3(2x-4)+21x=15

We move all terms to the left:

3(2x-4)+21x-(15)=0

We add all the numbers together, and all the variables

21x+3(2x-4)-15=0

We multiply parentheses

21x+6x-12-15=0

We add all the numbers together, and all the variables

27x-27=0

We move all terms containing x to the left, all other terms to the right

27x=27

x=27/27

x=1

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