3(2x-4)+3(-2x+5)+8(2x-7)=9(15-2x)

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Solution for 3(2x-4)+3(-2x+5)+8(2x-7)=9(15-2x) equation: 



3(2x-4)+3(-2x+5)+8(2x-7)=9(15-2x)

We move all terms to the left:

3(2x-4)+3(-2x+5)+8(2x-7)-(9(15-2x))=0

We add all the numbers together, and all the variables

3(2x-4)+3(-2x+5)+8(2x-7)-(9(-2x+15))=0

We multiply parentheses

6x-6x+16x-(9(-2x+15))-12+15-56=0



We calculate terms in parentheses: -(9(-2x+15)), so:

9(-2x+15)

We multiply parentheses

-18x+135

Back to the equation:

-(-18x+135)



We add all the numbers together, and all the variables

16x-(-18x+135)-53=0

We get rid of parentheses

16x+18x-135-53=0

We add all the numbers together, and all the variables

34x-188=0

We move all terms containing x to the left, all other terms to the right

34x=188

x=188/34

x=5+9/17

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