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3(2x-4)+3=12-x
We move all terms to the left:
3(2x-4)+3-(12-x)=0
We add all the numbers together, and all the variables
3(2x-4)-(-1x+12)+3=0
We multiply parentheses
6x-(-1x+12)-12+3=0
We get rid of parentheses
6x+1x-12-12+3=0
We add all the numbers together, and all the variables
7x-21=0
We move all terms containing x to the left, all other terms to the right
7x=21
x=21/7
x=3
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