3(2x-4)+3x=-3(x-8)

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Solution for 3(2x-4)+3x=-3(x-8) equation: 



3(2x-4)+3x=-3(x-8)

We move all terms to the left:

3(2x-4)+3x-(-3(x-8))=0

We add all the numbers together, and all the variables

3x+3(2x-4)-(-3(x-8))=0

We multiply parentheses

3x+6x-(-3(x-8))-12=0



We calculate terms in parentheses: -(-3(x-8)), so:

-3(x-8)

We multiply parentheses

-3x+24

Back to the equation:

-(-3x+24)



We add all the numbers together, and all the variables

9x-(-3x+24)-12=0

We get rid of parentheses

9x+3x-24-12=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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