3(2x-4)+3x=3(2x-4)+(5-x)

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Solution for 3(2x-4)+3x=3(2x-4)+(5-x) equation: 



3(2x-4)+3x=3(2x-4)+(5-x)

We move all terms to the left:

3(2x-4)+3x-(3(2x-4)+(5-x))=0

We add all the numbers together, and all the variables

3(2x-4)+3x-(3(2x-4)+(-1x+5))=0

We add all the numbers together, and all the variables

3x+3(2x-4)-(3(2x-4)+(-1x+5))=0

We multiply parentheses

3x+6x-(3(2x-4)+(-1x+5))-12=0



We calculate terms in parentheses: -(3(2x-4)+(-1x+5)), so:

3(2x-4)+(-1x+5)

We multiply parentheses

6x+(-1x+5)-12

We get rid of parentheses

6x-1x+5-12

We add all the numbers together, and all the variables

5x-7

Back to the equation:

-(5x-7)



We add all the numbers together, and all the variables

9x-(5x-7)-12=0

We get rid of parentheses

9x-5x+7-12=0

We add all the numbers together, and all the variables

4x-5=0

We move all terms containing x to the left, all other terms to the right

4x=5

x=5/4

x=1+1/4

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