3(2x-4)+4(3x+5)=42

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Solution for 3(2x-4)+4(3x+5)=42 equation: 



3(2x-4)+4(3x+5)=42

We move all terms to the left:

3(2x-4)+4(3x+5)-(42)=0

We multiply parentheses

6x+12x-12+20-42=0

We add all the numbers together, and all the variables

18x-34=0

We move all terms containing x to the left, all other terms to the right

18x=34

x=34/18

x=1+8/9

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