3(2x-4)+4(3x+6)=48

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Solution for 3(2x-4)+4(3x+6)=48 equation: 



3(2x-4)+4(3x+6)=48

We move all terms to the left:

3(2x-4)+4(3x+6)-(48)=0

We multiply parentheses

6x+12x-12+24-48=0

We add all the numbers together, and all the variables

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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