3(2x-4)+6=2(-x+12)+10

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Solution for 3(2x-4)+6=2(-x+12)+10 equation: 



3(2x-4)+6=2(-x+12)+10

We move all terms to the left:

3(2x-4)+6-(2(-x+12)+10)=0

We add all the numbers together, and all the variables

3(2x-4)-(2(-1x+12)+10)+6=0

We multiply parentheses

6x-(2(-1x+12)+10)-12+6=0



We calculate terms in parentheses: -(2(-1x+12)+10), so:

2(-1x+12)+10

We multiply parentheses

-2x+24+10

We add all the numbers together, and all the variables

-2x+34

Back to the equation:

-(-2x+34)



We add all the numbers together, and all the variables

6x-(-2x+34)-6=0

We get rid of parentheses

6x+2x-34-6=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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