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3(2x-4)+6=3-(x-3)
We move all terms to the left:
3(2x-4)+6-(3-(x-3))=0
We multiply parentheses
6x-(3-(x-3))-12+6=0
We calculate terms in parentheses: -(3-(x-3)), so:We add all the numbers together, and all the variables
3-(x-3)
determiningTheFunctionDomain -(x-3)+3
We get rid of parentheses
-x+3+3
We add all the numbers together, and all the variables
-1x+6
Back to the equation:
-(-1x+6)
6x-(-1x+6)-6=0
We get rid of parentheses
6x+1x-6-6=0
We add all the numbers together, and all the variables
7x-12=0
We move all terms containing x to the left, all other terms to the right
7x=12
x=12/7
x=1+5/7
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