3(2x-4)+6=3x+12

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Solution for 3(2x-4)+6=3x+12 equation: 



3(2x-4)+6=3x+12

We move all terms to the left:

3(2x-4)+6-(3x+12)=0

We multiply parentheses

6x-(3x+12)-12+6=0

We get rid of parentheses

6x-3x-12-12+6=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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