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3(2x-4)+6=5(x+2)
We move all terms to the left:
3(2x-4)+6-(5(x+2))=0
We multiply parentheses
6x-(5(x+2))-12+6=0
We calculate terms in parentheses: -(5(x+2)), so:We add all the numbers together, and all the variables
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
6x-(5x+10)-6=0
We get rid of parentheses
6x-5x-10-6=0
We add all the numbers together, and all the variables
x-16=0
We move all terms containing x to the left, all other terms to the right
x=16
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