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3(2x-4)-(3x+8)=x-2
We move all terms to the left:
3(2x-4)-(3x+8)-(x-2)=0
We multiply parentheses
6x-(3x+8)-(x-2)-12=0
We get rid of parentheses
6x-3x-x-8+2-12=0
We add all the numbers together, and all the variables
2x-18=0
We move all terms containing x to the left, all other terms to the right
2x=18
x=18/2
x=9
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