3(2x-4)-(4x+2)=-(-x-1)+10

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Solution for 3(2x-4)-(4x+2)=-(-x-1)+10 equation: 



3(2x-4)-(4x+2)=-(-x-1)+10

We move all terms to the left:

3(2x-4)-(4x+2)-(-(-x-1)+10)=0

We add all the numbers together, and all the variables

3(2x-4)-(4x+2)-(-(-1x-1)+10)=0

We multiply parentheses

6x-(4x+2)-(-(-1x-1)+10)-12=0

We get rid of parentheses

6x-4x-(-(-1x-1)+10)-2-12=0



We calculate terms in parentheses: -(-(-1x-1)+10), so:

-(-1x-1)+10

We get rid of parentheses

1x+1+10

We add all the numbers together, and all the variables

x+11

Back to the equation:

-(x+11)



We add all the numbers together, and all the variables

2x-(x+11)-14=0

We get rid of parentheses

2x-x-11-14=0

We add all the numbers together, and all the variables

x-25=0

We move all terms containing x to the left, all other terms to the right

x=25

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