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3(2x-4)-2(4x+1)=5(x-3)
We move all terms to the left:
3(2x-4)-2(4x+1)-(5(x-3))=0
We multiply parentheses
6x-8x-(5(x-3))-12-2=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
-2x-(5x-15)-14=0
We get rid of parentheses
-2x-5x+15-14=0
We add all the numbers together, and all the variables
-7x+1=0
We move all terms containing x to the left, all other terms to the right
-7x=-1
x=-1/-7
x=1/7
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