3(2x-4)-2x=4x-4(2x-5)

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Solution for 3(2x-4)-2x=4x-4(2x-5) equation: 



3(2x-4)-2x=4x-4(2x-5)

We move all terms to the left:

3(2x-4)-2x-(4x-4(2x-5))=0

We add all the numbers together, and all the variables

-2x+3(2x-4)-(4x-4(2x-5))=0

We multiply parentheses

-2x+6x-(4x-4(2x-5))-12=0



We calculate terms in parentheses: -(4x-4(2x-5)), so:

4x-4(2x-5)

We multiply parentheses

4x-8x+20

We add all the numbers together, and all the variables

-4x+20

Back to the equation:

-(-4x+20)



We add all the numbers together, and all the variables

4x-(-4x+20)-12=0

We get rid of parentheses

4x+4x-20-12=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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