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3(2x-4)-6(3x-5)=93
We move all terms to the left:
3(2x-4)-6(3x-5)-(93)=0
We multiply parentheses
6x-18x-12+30-93=0
We add all the numbers together, and all the variables
-12x-75=0
We move all terms containing x to the left, all other terms to the right
-12x=75
x=75/-12
x=-6+1/4
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