3(2x-4)-7(x+3)=4+(3+2x)-5(2+4x)

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Solution for 3(2x-4)-7(x+3)=4+(3+2x)-5(2+4x) equation: 



3(2x-4)-7(x+3)=4+(3+2x)-5(2+4x)

We move all terms to the left:

3(2x-4)-7(x+3)-(4+(3+2x)-5(2+4x))=0

We add all the numbers together, and all the variables

3(2x-4)-7(x+3)-(4+(2x+3)-5(4x+2))=0

We multiply parentheses

6x-7x-(4+(2x+3)-5(4x+2))-12-21=0



We calculate terms in parentheses: -(4+(2x+3)-5(4x+2)), so:

4+(2x+3)-5(4x+2)

determiningTheFunctionDomain
(2x+3)-5(4x+2)+4

We multiply parentheses

(2x+3)-20x-10+4

We get rid of parentheses

2x-20x+3-10+4

We add all the numbers together, and all the variables

-18x-3

Back to the equation:

-(-18x-3)



We add all the numbers together, and all the variables

-1x-(-18x-3)-33=0

We get rid of parentheses

-1x+18x+3-33=0

We add all the numbers together, and all the variables

17x-30=0

We move all terms containing x to the left, all other terms to the right

17x=30

x=30/17

x=1+13/17

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