3(2x-4)-7(x-8)=2+3(-x+4)-(2-x)

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Solution for 3(2x-4)-7(x-8)=2+3(-x+4)-(2-x) equation: 



3(2x-4)-7(x-8)=2+3(-x+4)-(2-x)

We move all terms to the left:

3(2x-4)-7(x-8)-(2+3(-x+4)-(2-x))=0

We add all the numbers together, and all the variables

3(2x-4)-7(x-8)-(2+3(-1x+4)-(-1x+2))=0

We multiply parentheses

6x-7x-(2+3(-1x+4)-(-1x+2))-12+56=0



We calculate terms in parentheses: -(2+3(-1x+4)-(-1x+2)), so:

2+3(-1x+4)-(-1x+2)

determiningTheFunctionDomain
3(-1x+4)-(-1x+2)+2

We multiply parentheses

-3x-(-1x+2)+12+2

We get rid of parentheses

-3x+1x-2+12+2

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We add all the numbers together, and all the variables

-1x-(-2x+12)+44=0

We get rid of parentheses

-1x+2x-12+44=0

We add all the numbers together, and all the variables

x+32=0

We move all terms containing x to the left, all other terms to the right

x=-32

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