3(2x-4)=2(-x+2)

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Solution for 3(2x-4)=2(-x+2) equation: 



3(2x-4)=2(-x+2)

We move all terms to the left:

3(2x-4)-(2(-x+2))=0

We add all the numbers together, and all the variables

3(2x-4)-(2(-1x+2))=0

We multiply parentheses

6x-(2(-1x+2))-12=0



We calculate terms in parentheses: -(2(-1x+2)), so:

2(-1x+2)

We multiply parentheses

-2x+4

Back to the equation:

-(-2x+4)



We get rid of parentheses

6x+2x-4-12=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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