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3(2x-4)=2(2x+2)
We move all terms to the left:
3(2x-4)-(2(2x+2))=0
We multiply parentheses
6x-(2(2x+2))-12=0
We calculate terms in parentheses: -(2(2x+2)), so:We get rid of parentheses
2(2x+2)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
6x-4x-4-12=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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