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3(2x-4)=2(2x+2)+2x
We move all terms to the left:
3(2x-4)-(2(2x+2)+2x)=0
We multiply parentheses
6x-(2(2x+2)+2x)-12=0
We calculate terms in parentheses: -(2(2x+2)+2x), so:We get rid of parentheses
2(2x+2)+2x
We add all the numbers together, and all the variables
2x+2(2x+2)
We multiply parentheses
2x+4x+4
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
6x-6x-4-12=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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