3(2x-4)=2(3-x)+6

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Solution for 3(2x-4)=2(3-x)+6 equation: 



3(2x-4)=2(3-x)+6

We move all terms to the left:

3(2x-4)-(2(3-x)+6)=0

We add all the numbers together, and all the variables

3(2x-4)-(2(-1x+3)+6)=0

We multiply parentheses

6x-(2(-1x+3)+6)-12=0



We calculate terms in parentheses: -(2(-1x+3)+6), so:

2(-1x+3)+6

We multiply parentheses

-2x+6+6

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

6x+2x-12-12=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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