3(2x-4)=2(3x-1)-10

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Solution for 3(2x-4)=2(3x-1)-10 equation:


Simplifying
3(2x + -4) = 2(3x + -1) + -10

Reorder the terms:
3(-4 + 2x) = 2(3x + -1) + -10
(-4 * 3 + 2x * 3) = 2(3x + -1) + -10
(-12 + 6x) = 2(3x + -1) + -10

Reorder the terms:
-12 + 6x = 2(-1 + 3x) + -10
-12 + 6x = (-1 * 2 + 3x * 2) + -10
-12 + 6x = (-2 + 6x) + -10

Reorder the terms:
-12 + 6x = -2 + -10 + 6x

Combine like terms: -2 + -10 = -12
-12 + 6x = -12 + 6x

Add '12' to each side of the equation.
-12 + 12 + 6x = -12 + 12 + 6x

Combine like terms: -12 + 12 = 0
0 + 6x = -12 + 12 + 6x
6x = -12 + 12 + 6x

Combine like terms: -12 + 12 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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