3(2x-4)=2(6+x)-(x+4)

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Solution for 3(2x-4)=2(6+x)-(x+4) equation:



3(2x-4)=2(6+x)-(x+4)
We move all terms to the left:
3(2x-4)-(2(6+x)-(x+4))=0
We add all the numbers together, and all the variables
3(2x-4)-(2(x+6)-(x+4))=0
We multiply parentheses
6x-(2(x+6)-(x+4))-12=0
We calculate terms in parentheses: -(2(x+6)-(x+4)), so:
2(x+6)-(x+4)
We multiply parentheses
2x-(x+4)+12
We get rid of parentheses
2x-x-4+12
We add all the numbers together, and all the variables
x+8
Back to the equation:
-(x+8)
We get rid of parentheses
6x-x-8-12=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4

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