3(2x-4)=2(6+x)-(x+4)

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Solution for 3(2x-4)=2(6+x)-(x+4) equation: 



3(2x-4)=2(6+x)-(x+4)

We move all terms to the left:

3(2x-4)-(2(6+x)-(x+4))=0

We add all the numbers together, and all the variables

3(2x-4)-(2(x+6)-(x+4))=0

We multiply parentheses

6x-(2(x+6)-(x+4))-12=0



We calculate terms in parentheses: -(2(x+6)-(x+4)), so:

2(x+6)-(x+4)

We multiply parentheses

2x-(x+4)+12

We get rid of parentheses

2x-x-4+12

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We get rid of parentheses

6x-x-8-12=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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