3(2x-4)=2(x+12)

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Solution for 3(2x-4)=2(x+12) equation: 



3(2x-4)=2(x+12)

We move all terms to the left:

3(2x-4)-(2(x+12))=0

We multiply parentheses

6x-(2(x+12))-12=0



We calculate terms in parentheses: -(2(x+12)), so:

2(x+12)

We multiply parentheses

2x+24

Back to the equation:

-(2x+24)



We get rid of parentheses

6x-2x-24-12=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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